p^2+2p(0.0667)+(.0667)^2=1

Solution for p^2+2p(0.0667)+(.0667)^2=1 equation:

p^2+2p(0.0667)+(.0667)^2=1

We move all terms to the left:

p^2+2p(0.0667)+(.0667)^2-(1)=0

determiningTheFunctionDomain
p^2+2p(0.0667)-1+(.0667)^2=0

We add all the numbers together, and all the variables

p^2+2p(0.0667)-1+(0.0667)^2=0

We add all the numbers together, and all the variables

p^2+2p(0.0667)-0.99555111=0

We multiply parentheses

p^2+0.1334p-0.99555111=0

a = 1; b = 0.1334; c = -0.99555111;
Δ = b2-4ac
Δ = 0.13342-4·1·(-0.99555111)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.1334)-2}{2*1}=\frac{-2.1334}{2}
=-1+0.1334/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.1334)+2}{2*1}=\frac{1.8666}{2}
=1/1.0714668381014
$